80m^2-405=0

Solution for 80m^2-405=0 equation:

80m^2-405=0

a = 80; b = 0; c = -405;
Δ = b2-4ac
Δ = 02-4·80·(-405)
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-360}{2*80}=\frac{-360}{160}
=-2+1/4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+360}{2*80}=\frac{360}{160}
=2+1/4
$